Science, Tech, Math › Science Atomic Mass From Atomic Abundance Chemistry Problem Worked Atomic Abundance Chemistry Problem Share Flipboard Email Print The atomic weight of an element is a weighted ratio of atomic weights. For boron, this means the number of neutrons in an atom isn't always 5. ROGER HARRIS/SCIENCE PHOTO LIBRARY / Getty Images Science Chemistry Basics Chemical Laws Molecules Periodic Table Projects & Experiments Scientific Method Biochemistry Physical Chemistry Medical Chemistry Chemistry In Everyday Life Famous Chemists Activities for Kids Abbreviations & Acronyms Biology Physics Geology Astronomy Weather & Climate By Anne Marie Helmenstine, Ph.D. Anne Marie Helmenstine, Ph.D. Facebook Twitter Chemistry Expert Ph.D., Biomedical Sciences, University of Tennessee at Knoxville B.A., Physics and Mathematics, Hastings College Dr. Helmenstine holds a Ph.D. in biomedical sciences and is a science writer, educator, and consultant. She has taught science courses at the high school, college, and graduate levels. Learn about our Editorial Process Updated on August 06, 2019 You may have noticed the atomic mass of an element isn't the same as the sum of the protons and neutrons of a single atom. This is because elements exist as multiple isotopes. While each atom of an element has the same number of protons, it can have a variable number of neutrons. The atomic mass on the periodic table is a weighted average of the atomic masses of atoms observed in all samples of that element. You can use the atomic abundance to calculate the atomic mass of any element sample if you know the percentage of each isotope. Atomic Abundance Example Chemistry Problem The element boron consists of two isotopes, 105B and 115B. Their masses, based on the carbon scale, are 10.01 and 11.01, respectively. The abundance of 105B is 20.0% and the abundance of 115B is 80.0%. What is the atomic mass of boron? Solution: The percentages of multiple isotopes must add up to 100%. Apply the following equation to the problem: atomic mass = (atomic mass X1) · (% of X1)/100 + (atomic mass X2) · (% of X2)/100 + ...where X is an isotope of the element and % of X is the abundance of the isotope X. Substitute the values for boron in this equation: atomic mass of B = (atomic mass of 105B · % of 105B/100) + (atomic mass of 115B · % of 115B/100)atomic mass of B = (10.01· 20.0/100) + (11.01· 80.0/100)atomic mass of B = 2.00 + 8.81atomic mass of B = 10.81 Answer: The atomic mass of boron is 10.81. Note that this is the value listed in the periodic table for the atomic mass of boron. Although the atomic number of boron is 10, its atomic mass is nearer to 11 than to 10, reflecting the fact that the heavier isotope is more abundant than the lighter isotope. Why Aren't Electrons Included? The number and mass of electrons is not included in an atomic mass calculation because the mass of the electron is infinitesimal compared to that of a proton or neutron. Basically, electrons don't significantly affect the mass of an atom. Cite this Article Format mla apa chicago Your Citation Helmenstine, Anne Marie, Ph.D. "Atomic Mass From Atomic Abundance Chemistry Problem." ThoughtCo, Aug. 26, 2020, thoughtco.com/atomic-mass-from-atomic-abundance-problem-609540. Helmenstine, Anne Marie, Ph.D. (2020, August 26). Atomic Mass From Atomic Abundance Chemistry Problem. Retrieved from https://www.thoughtco.com/atomic-mass-from-atomic-abundance-problem-609540 Helmenstine, Anne Marie, Ph.D. "Atomic Mass From Atomic Abundance Chemistry Problem." ThoughtCo. https://www.thoughtco.com/atomic-mass-from-atomic-abundance-problem-609540 (accessed June 9, 2023). copy citation