Science, Tech, Math › Science Briggs-Rauscher Oscillating Color Change Reaction Share Flipboard Email Print GIPhotoStock / Getty Images Science Chemistry Projects & Experiments Basics Chemical Laws Molecules Periodic Table Scientific Method Biochemistry Physical Chemistry Medical Chemistry Chemistry In Everyday Life Famous Chemists Activities for Kids Abbreviations & Acronyms Biology Physics Geology Astronomy Weather & Climate By Anne Marie Helmenstine, Ph.D. Chemistry Expert Ph.D., Biomedical Sciences, University of Tennessee at Knoxville B.A., Physics and Mathematics, Hastings College Dr. Helmenstine holds a Ph.D. in biomedical sciences and is a science writer, educator, and consultant. She has taught science courses at the high school, college, and graduate levels. our editorial process Facebook Facebook Twitter Twitter Anne Marie Helmenstine, Ph.D. Updated July 03, 2019 The Briggs-Rauscher reaction, also known as 'the oscillating clock', is one of the most common demonstrations of a chemical oscillator reaction. The reaction begins when three colorless solutions are mixed together. The color of the resulting mixture will oscillate between clear, amber, and deep blue for about 3-5 minutes. The solution ends up as a blue-black mixture. Solution A Add 43 g potassium iodate (KIO3) to ~800 mL distilled water. Stir in 4.5 mL sulfuric acid (H2SO4). Continue stirring until the potassium iodate is dissolved. Dilute to 1 L. Solution B Add 15.6 g malonic acid (HOOCCH2COOH) and 3.4 g manganese sulfate monohydrate (MnSO4 . H2O) to ~800 mL distilled water. Add 4 g of vitex starch. Stir until dissolved. Dilute to 1 L. Solution C Dilute 400 mL of 30% hydrogen peroxide (H2O2) to 1 L. Materials 300 mL of each solution1 L beakerstirring platemagnetic stir bar Procedure Place the stirring bar into the large beaker.Pour 300 mL each of solutions A and B into the beaker.Turn on the stirring plate. Adjust the speed to produce a large vortex.Add 300 mL of solution C into the beaker. Be sure to add solution C after mixing solutions A + B or else the demonstration will not work. Enjoy! Notes This demonstration evolves iodine. Wear safety goggles and gloves and perform the demonstration in a well-ventilated room, preferably under a ventilation hood. Use care when preparing the solutions, as the chemicals include strong irritants and oxidizing agents. Clean Up Neutralize the iodine by reducing it to iodide. Add ~10 g sodium thiosulfate to the mixture. Stir until the mixture becomes colorless. The reaction between iodine and thiosulfate is exothermic and the mixture may be hot. Once cool, the neutralized mixture may be washed down the drain with water. The Briggs-Rauscher Reaction IO3- + 2 H2O2 + CH2(CO2H)2 + H+ --> ICH(CO2H)2 + 2 O2 + 3 H2O This reaction can be broken into two component reactions: IO3- + 2 H2O2 + H+ --> HOI + 2 O2 + 2 H2O This reaction can occur by a radical process which is turned on when I- concentration is low, or by a nonradical process when the I- concentration is high. Both processes reduce iodate to hypoiodous acid. The radical process forms hypoiodous acid at a much faster rate than the nonradical process. The HOI product of the first component reaction is a reactant in the second component reaction: HOI + CH2(CO2H)2 --> ICH(CO2H)2 + H2O This reaction also consists of two component reactions: I- + HOI + H+ --> I2 + H2O I2CH2(CO2H)2 --> ICH2(CO2H)2 + H+ + I- The amber color results from the production of the I2. The I2 forms because of the rapid production of HOI during the radical process. When the radical process is occurring, HOI is created faster than it can be consumed. Some of the HOI is used while excess is reduced by hydrogen peroxide to I-. The increasing I- concentration reaches a point at which the nonradical process takes over. However, the nonradical process does not produce HOI nearly as fast as the radical process, so the amber color begins to clear as I2 is consumed more quickly than it can be created. Eventually the I- concentration drops low enough for the radical process to restart so the cycle can repeat itself. The deep blue color is the result of the I- and I2 binding to the starch present in the solution. Source B. Z. Shakhashiri, 1985, Chemical Demonstrations: A Handbook for Teachers of Chemistry, vol. 2, pp. 248-256.