How to Calculate Osmotic Pressure Example Problem

The osmotic pressure of a sugar solution indicates how readily water could diffuse into the solution across a semipermeable membrane.
The osmotic pressure of a sugar solution indicates how readily water could diffuse into the solution across a semipermeable membrane. David Murray and Jules Selmes / Getty Images

The osmotic pressure of a solution is the minimum amount of pressure needed to prevent water from flowing into it across a semipermeable membrane. Osmotic pressure also reflects how readily water can enter the solution via osmosis, as across a cell membrane. For a dilute solution, osmotic pressure obeys a form of the ideal gas law and can be calculated providing you know the concentration of the solution and the temperature.

This example problem demonstrates how to calculate the osmotic pressure of a solution of sucrose (table sugar) in water.

Osmotic Pressure Problem

What is the osmotic pressure of a solution prepared by adding 13.65 g of sucrose (C12H22O11) to enough water to make 250 mL of solution at 25 °C?


Osmosis and osmotic pressure are related. Osmosis is the flow of a solvent into a solution through a semipermiable membrane. Osmotic pressure is the pressure that stops the process of osmosis. Osmotic pressure is a colligative property of a substance since it depends on the concentration of the solute and not its chemical nature.

Osmotic pressure is expressed by the formula:

Π = iMRT (note how it resembles the PV = nRT form of the Ideal Gas Law)

Π is the osmotic pressure in atm
i = van 't Hoff factor of the solute
M = molar concentration in mol/L
R = universal gas constant = 0.08206 L·atm/mol·K
T = absolute temperature in K

Step 1: - Find concentration of sucrose.

To do this, look up the atomic weights of the elements in the compound:

From the periodic table:
C = 12 g/mol
H = 1 g/mol
O = 16 g/mol

Use the atomic weights to find the molar mass of the compound. Multiply the subscripts in the formula times the atomic weight of the element. If there is no subscript, it means one atom is present.

molar mass of sucrose = 12(12) + 22(1) + 11(16)
molar mass of sucrose = 144 + 22 + 176
molar mass of sucrose = 342

nsucrose = 13.65 g x 1 mol/342 g
nsucrose = 0.04 mol

Msucrose = nsucrose/Volumesolution
Msucrose = 0.04 mol/(250 mL x 1 L/1000 mL)
Msucrose = 0.04 mol/0.25 L
Msucrose = 0.16 mol/L

Step 2: - Find absolute temperature. Remember, absolute temperature is always given in Kelvin. If the temperature is given in Celsius or Fahrenheit, convert it to Kelvin.

T = °C + 273
T = 25 + 273
T = 298 K

Step 3: - Determine the van 't Hoff factor

Sucrose does not dissociate in water; therefore the van 't Hoff factor = 1.

Step 4: - Find osmotic pressure by plugging the values into the equation.

Π = iMRT
Π = 1 x 0.16 mol/L x 0.08206 L·atm/mol·K x 298 K
Π = 3.9 atm


The osmotic pressure of ​the sucrose solution is 3.9 atm.

Tips for Solving Osmotic Pressure Problems

The biggest issue when solving the problem is knowing the van't Hoff factor and using the correct units for terms in the equation. If a solution dissolves in water (e.g., sodium chloride), it's necessary to either have the van't Hoff factor given or else look it up. Work in units of atmospheres for pressure, Kelvin for temperature, moles for mass, and liters for volume.

Watch significant figures if unit conversions are required.