Science, Tech, Math › Science Heat Capacity Example Problem Calculate the heat needed to raise water from freezing to boiling Share Flipboard Email Print Erika Straesser / EyeEm / Getty Images Science Chemistry Basics Chemical Laws Molecules Periodic Table Projects & Experiments Scientific Method Biochemistry Physical Chemistry Medical Chemistry Chemistry In Everyday Life Famous Chemists Activities for Kids Abbreviations & Acronyms Biology Physics Geology Astronomy Weather & Climate By Todd Helmenstine Todd Helmenstine is a science writer and illustrator who has taught physics and math at the college level. He holds bachelor's degrees in both physics and mathematics. our editorial process Todd Helmenstine Updated September 13, 2019 Heat capacity is the amount of heat energy required to change the temperature of a substance. This example problem demonstrates how to calculate heat capacity. Problem: Heat Capacity of Water From Freezing to Boiling Point What is the heat in joules required to raise the temperature of 25 grams of water from 0 degrees C to 100 degrees C? What is the heat in calories? Useful information: specific heat of water = 4.18 J/g·°CSolution: Part I Use the formula q = mcΔTwhereq = heat energym = massc = specific heatΔT = change in temperatureq = (25 g)x(4.18 J/g·°C)[(100 C - 0 C)]q = (25 g)x(4.18 J/g·°C)x(100 C)q = 10450 JPart II4.18 J = 1 caloriex calories = 10450 J x (1 cal/4.18 J)x calories = 10450/4.18 caloriesx calories = 2500 caloriesAnswer:10450 J or 2500 calories of heat energy are required to raise the temperature of 25 grams of water from 0 degrees C to 100 degrees C. Tips for Success The most common mistake people make with this calculation is using incorrect units. Make certain temperatures are in Celsius. Convert kilograms to grams.Be mindful of significant figures, particularly when working problems for homework or an exam.