# Percent Composition by Mass Example

## Worked Chemistry Problems

Percent composition by mass is a statement of the percent mass of each element in a chemical compound or the percent mass of components of a solution or alloy. This worked example chemistry problem works through the steps to calculate percent composition by mass. The example is for a sugar cube dissolved in a cup of water.

## Percent Composition by Mass Question

A 4 g sugar cube (Sucrose: C12H22O11) is dissolved in a 350 ml teacup of 80 °C water. What is the percent composition by mass of the sugar solution?

Given: Density of water at 80 °C = 0.975 g/ml

## Percent Composition Definition

Percent Composition by Mass is the mass of the solute divided by the mass of the solution (mass of the solute plus mass of the solvent), multiplied by 100.

## How to Solve the Problem

Step 1 - Determine mass of solute

We were given the mass of the solute in the problem. The solute is the sugar cube.

masssolute = 4 g of C12H22O11

Step 2 - Determine mass of solvent

The solvent is the 80 °C water. Use the density of the water to find the mass.

density = mass/volume

mass = density x volume

mass = 0.975 g/ml x 350 ml

masssolvent = 341.25 g

Step 3 - Determine the total mass of the solution

msolution = msolute + msolvent

msolution = 4 g + 341.25 g

msolution = 345.25 g

Step 4 - Determine percent composition by mass of the sugar solution.

percent composition = (msolute / msolution) x 100

percent composition = ( 4 g / 345.25 g) x 100

percent composition = ( 0.0116) x 100