Science, Tech, Math › Science What the Compton Effect Is and How It Works in Physics Share Flipboard Email Print generalfmv / Getty Images Science Physics Quantum Physics Physics Laws, Concepts, and Principles Important Physicists Thermodynamics Cosmology & Astrophysics Chemistry Biology Geology Astronomy Weather & Climate By Andrew Zimmerman Jones Math and Physics Expert M.S., Mathematics Education, Indiana University B.A., Physics, Wabash College Andrew Zimmerman Jones is a science writer, educator, and researcher. He is the co-author of "String Theory for Dummies." our editorial process Andrew Zimmerman Jones Updated March 26, 2018 The Compton effect (also called Compton scattering) is the result of a high-energy photon colliding with a target, which releases loosely bound electrons from the outer shell of the atom or molecule. The scattered radiation experiences a wavelength shift that cannot be explained in terms of classical wave theory, thus lending support to Einstein's photon theory. Probably the most important implication of the effect is that it showed light could not be fully explained according to wave phenomena. Compton scattering is one example of a type of inelastic scattering of light by a charged particle. Nuclear scattering also occurs, although the Compton effect typically refers to the interaction with electrons. The effect was first demonstrated in 1923 by Arthur Holly Compton (for which he received a 1927 Nobel Prize in Physics). Compton's graduate student, Y.H. Woo, later verified the effect. How Compton Scattering Works The scattering is demonstrated is pictured in the diagram. A high-energy photon (generally X-ray or gamma-ray) collides with a target, which has loosely-bound electrons in its outer shell. The incident photon has the following energy E and linear momentum p: E = hc / lambdap = E / c The photon gives part of its energy to one of the almost-free electrons, in the form of kinetic energy, as expected in a particle collision. We know that total energy and linear momentum must be conserved. Analyzing these energy and momentum relationships for the photon and electron, you end up with three equations: energyx-component momentumy-component momentum ... in four variables: phi, the scattering angle of the electrontheta, the scattering angle of the photonEe, the final energy of the electronE', the final energy of the photon If we care only about the energy and direction of the photon, then the electron variables can be treated as constants, meaning that it's possible to solve the system of equations. By combining these equations and using some algebraic tricks to eliminate variables, Compton arrived at the following equations (which are obviously related, since energy and wavelength are related to photons): 1 / E' - 1 / E = 1/( me c 2) * (1 - cos theta)lambda' - lambda = h/(me c) * (1 - cos theta) The value h/(me c) is called the Compton wavelength of the electron and has a value of 0.002426 nm (or 2.426 x 10-12 m). This isn't, of course, an actual wavelength, but really a proportionality constant for the wavelength shift. Why Does This Support Photons? This analysis and derivation are based on a particle perspective and the results are easy to test. Looking at the equation, it becomes clear that the entire shift can be measured purely in terms of the angle at which the photon gets scattered. Everything else on the right side of the equation is a constant. Experiments show that this is the case, giving great support to the photon interpretation of light. Edited by Anne Marie Helmenstine, Ph.D.