Theoretical Yield Example Problem

Calculate the Amount of Product Produced From Given Amount of Reactant

You can calculate the theoretical yield of a chemical reaction.
You can calculate the theoretical yield of a chemical reaction to know about how much product to expect. Ben Mills

This example problem demonstrates how to predict the amount of product produced from a given amount of reactants.

Problem

Given the reaction

Na2S(aq) + 2 AgNO3(aq) → Ag2S(s) + 2 NaNO3(aq)

How many grams of Ag2S will form when 3.94 g of AgNO3 and an excess of Na2S are reacted together?

Solution

The key to solve this type of problem is to find the mole ratio between the product and the reactant.

Step 1 - Find the atomic weight of AgNO3 and Ag2S.



From the periodic table:

Atomic weight of Ag = 107.87 g
Atomic weight of N = 14 g
Atomic weight of O = 16 g
Atomic weight of S = 32.01 g

Atomic weight of AgNO3 = (107.87 g) + (14.01 g) + 3(16.00 g)
Atomic weight of AgNO3 = 107.87 g + 14.01 g + 48.00 g
Atomic weight of AgNO3 = 169.88 g

Atomic weight of Ag2S = 2(107.87 g) + 32.01 g
Atomic weight of Ag2S = 215.74 g + 32.01 g
Atomic weight of Ag2S = 247.75 g

Step 2 - Find mole ratio between product and reactant

The reaction formula gives the whole number of moles needed to complete and balance the reaction. For this reaction, two moles of AgNO3 is needed to produce one mole of Ag2S.

The mole ratio then is 1 mol Ag2S/2 mol AgNO3

Step 3 Find amount of product produced.

The excess of Na2S means all of the 3.94 g of AgNO3 will be used to complete the reaction.

grams Ag2S = 3.94 g AgNO3 x 1 mol AgNO3/169.88 g AgNO3 x 1 mol Ag2S/2 mol AgNO3 x 247.75 g Ag2S/1 mol Ag2S

Note the units cancel out, leaving only grams Ag2S

grams Ag2S = 2.87 g Ag2S

Answer

2.87 g of Ag2S will be produced from 3.94 g of AgNO3.